Just to add a little spice.
During the load testing of the Europa in Germany the elevator must be
loaded symetrically with 150 Kg and then on one side only with 100 Kg.
All systems must move freely.
This seems to me to be quite a lot of weight but it takes it without
problems and no deflection.
Barry Tennant
Fred Fillinger schrieb:
>
> I can agree with Duncan's basic premise that the torque tube is
> equally strong in both directions, and let's assume ditto for strength
> of the fuselage. The ultimate question is how much strength that is.
> Whatever load is on the tail while pulling +3.8G's, when deflected in
> the opposite direction at equal loading on the tail, will place twice
> the load limit of -1.9G on the wings. Actually more, since the plane
> is nose heavy if loaded within CG limits, so the tail doesn't have to
> work as hard in negative G's. So looks to me, theoretically the wings
> should break before the tail does.
>
> Best,
> Fred F.
>
> > Duncan
> >
> > Your symmetrical loading theory is probably erroneous. The stabilator is
> > normally loaded downward (negative lift) when it is in a neutral position.
> > Therefore, it will take less downward deflection to reach the critical
> > (breaking) point. Upward deflection (12 degrees) gets to overcome the
> > downward
> > loading before it even starts to give positive lift loads as it deflects
> > upward.
> >
> > Regards
> >
> > Tom Friedland A079
> >
> > McFadyean wrote:
> >
> > > All true. Only the structure of the tailplane and its support is
> > > symmetrical in a vertical plane. So if it will take 12 degrees or so in
> > > the
> > > "up" direction then it should take similarly in the "down" direction.
> > >
> > > Duncan McFadyean
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