| Subject: | Alternator warning lamp | 
|---|---|
| From: | Barahona Alonso Francisco Javier <javier.barahona@aeasa.com> | 
| Date: | Thu, 20 Jul 2000 08:16:07 | 
| 
Dear friends,
Months ago somebody advised me about the possibility of substituting the
alternator warning lamp (3W, 12V) for a diode plus a 480 Ohms resistor.
Making calculations I obtain that I need a resistor of 48 Ohms instead:
        R = (V
2)/P = (12
2)/3 = 48
I do not know which is the resistance of the diode. Could somebody confirm
me which of both resistors, 48 or 480 Ohms should I use?
Best regards.
Javier Barahona (Classic #187)
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