Subject: | Alternator warning lamp |
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From: | Barahona Alonso Francisco Javier <javier.barahona@aeasa.com> |
Date: | Thu, 20 Jul 2000 08:16:07 |
Dear friends, Months ago somebody advised me about the possibility of substituting the alternator warning lamp (3W, 12V) for a diode plus a 480 Ohms resistor. Making calculations I obtain that I need a resistor of 48 Ohms instead: R = (V 2)/P = (12 2)/3 = 48 I do not know which is the resistance of the diode. Could somebody confirm me which of both resistors, 48 or 480 Ohms should I use? Best regards. Javier Barahona (Classic #187) |
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